Problem:
2x +10x + 12x x + 7
____________ * _____
2x + 10x x² − 9
↓
2x(x +5x +6) x + 7
__________ * ________ (Factor it Out)
2x(x + 5) (x+3)(x−3)
↓
2x(x+2)(x+3) x + 7
____________ * _______ (Cross Out)
2x(x + 5) (x+3)(x−3)
↓
(x+2) (x +7) x² +9x + 14 (Multiply Remaining Factors)
______ * ______ = ___________
(x+5) (x−3) x² +2x − 15
↓
x² +9x + 14
__________ (x cannot equal; 0, 3,−3,−5)
x² +2x − 15
DIVIDING:
First you start out by using KCF (Keep, Change, Flip) which is the multiplication of reciprocal.
Problem :
x + 7 x² + 9x + 14 x + 7 3x² - 9x
____ / ___________ KCF _____ * __________
x² − 9 3x² − 9x x² − 9 x² + 9x + 14
Step 2: Factor out everything that needs to be factored.
x + 7 3x(x − 3)
_________ * ________
(x− 3)(x+3) (x+7)(x+2)
Step 3: Cancel out the common factors
x + 7 3x(x − 3)
_________ * ________
(x− 3)(x+3) (x+7)(x+2)
Step 4: Multiply the remaining factors of the numerator & denominator.
3x 3x
_________ * ____________
(x+2)(x+3) x² + 5X + 6
Final Answer
__________ (x cannot equal; 0,−2,3,−7,−3)
x² + 5X + 6
http://www.mathwarehouse.com/algebra/rational-expression/how-to-multiply-divide-rational-expressions.php
tough to read the white writing on white background...
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